1 ) The length of tube of a microscope is 10 cm . The focal length of the objective and eye lens are 0.5 cm and 1.0 cm . The magnifying power of microscope is about : -
A ) 221 , B ) 500 ,
C ) 891 , D ) None of these ,
Correct Answer : - B ) 500 ,
Solution : -
So , it is compound microscope .
M = ( L D ) / ( fo fe ) .
∴ L = length of tube = 10 cm ,
∴ fo = 0.1 cm , fe = 1 cm .
∴ D = least distance of distinct vision = 25 cm .
So , M = (10 x 25 ) / (0.5 x 1 ) = 500 , Answer .
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2 ) A compound microscope has a magnifying power of 100 when the image is formed at infinity . The objective has a focal length of 0.5 cm and the tube length is 6.5 cm . Find the focal length of the eye piece : -
A ) 2 cm , B ) 8.4 cm ,
C ) 11 cm , D ) None of these ,
Correct Answer : - A ) 2 cm ,
Solution : -
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